Q. What is the melting point of tin?

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Q. Which one is having a maximum melting point?

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Q. What is the melting point of palladium?

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Q. What is the melting point of nichrome?

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Q. Which one is having a minimum melting point?

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Q. What is the melting point of germanium?

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Q. Which one is having the highest melting point?

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Q. What is the melting point of cobalt?

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Q. What is the melting point of chromium?

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Q. Sherwood number is a function of

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Q. The expression for average mass transfer coefficient is

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Q. The empirical correlation for local mass transfer coefficient for turbulent boundary layer flow past a flat plate is given by

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Q. The empirical correlation for local mass transfer coefficient for laminar boundary layer flow past a flat plate is given by

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Q. Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine value of Sherwood number for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of air.

D =0.82 * 10⁻⁶ m²/s
v = 15.5 * 10⁻⁶ m²/s

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Q. Air at 1 atm and 25 degree Celsius temperature, flows inside a 3 cm diameter tube with a velocity of 5.25 m/s. Determine mass transfer coefficient for iodine transfer from the air stream to the weak surface. Assume the following thermos-physical properties of air.

D =0.82 * 10⁻⁶ m²/s
v = 15.5 * 10⁻⁶ m²/s

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Q. Assume the following thermos-physical properties of air.

D =0.82 * 10⁻⁶ m²/s
v = 15.5 * 10⁻⁶ m²/s

Find the value of Schmidt number.

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Q. Air at 30 degree Celsius temperature flows at 45 m/s past a wet flat plate of length 0.5 m. Estimate the value of Reynolds number. Assume that the water vapor content of air initially is negligible and take the following thermos-physical properties of air.

D = 0.256 * 10⁻⁴ m²/s
µ = 1.86 * 10⁻⁵ kg/m s
cₚ = 1.005 k J/kg degree Celsius
pᵣ = 0.701
p =1.165 kg/m³

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Q. Air at 30 degree Celsius temperature flows at 45 m/s past a wet flat plate of length 0.5 m. Estimate the value of mass transfer coefficient. Assume that the water vapor content of air initially is negligible and take the following thermos-physical properties of air.

D = 0.256 * 10⁻⁴ m²/s
µ = 1.86 * 10⁻⁵ kg/m s
cₚ = 1.005 k J/kg degree Celsius
pᵣ = 0.701
p =1.165 kg/m³

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Q. Assume the following thermos-physical properties of air

D = 0.256 * 10⁻⁴ m²/s
µ = 1.86 * 10⁻⁵ kg/m s
cₚ = 1.005 k J/kg degree Celsius
pᵣ = 0.701
p =1.165 kg/m³

Find the value of Schmidt number.

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Q. What is the density of oak in kg/m³?

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