Question

In case of immobilized enzymes, the equation \(V=K_L ([S_0]-[S])=\frac{V_{max} [S]}{K_m+S+\frac{S^2}{K_S}}\) represents ______________ inhibition.

a.

substrate

b.

product

c.

uncompetitive

d.

competitive

Posted under Enzyme Technology

Answer: (a).substrate

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Q. In case of immobilized enzymes, the equation \(V=K_L ([S_0]-[S])=\frac{V_{max} [S]}{K_m+S+\frac{S^2}{K_S}}\) represents ______________ inhibition.
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