Q. In the circuit of figure diode will conduct

View solution

Q. In figure, V0 =

View solution

Q. The JFET in the circuit shown in figure has an IDSS = 10 mA and Vp = -5V. The value of the resistance Rs for a drain current IDS = 6.4 mA is

View solution

Q. In figure, V0 =

View solution

Q. In the op-amp circuit of figure, V0 =

View solution

Q. In figure the zener has a resistance of 5 ohms. As the load resistance is varied, the output voltage

View solution

Q. The transistor of following figure in Si diode with a base current of 40 μA and ICBO = 0, if VBB = 6V, RE = 2 kΩ and β = 90, IBQ = 20 μA then IEQ =

View solution

Q. In the CE circuit shown in figure the slope of ac load line will be

View solution

Q. The op-amp circuit shown in the figure is a filter. The type of filter and its cut off type of filter and its cut off frequency are respectively.

View solution

Q. In the circuit of figure, PIV can be up to

View solution

Q. In the circuit of figure β = 50 and VBE = 0.5 V. The quiescent value of base current IB is

View solution

Q. In figure the input and output Miller capacitances are

View solution

Q. Figure uses 10 V zener diode. The minimum and maximum current through series resistance are

View solution

Q. When Z1 << Z, The circuit of figure works as

View solution

Q. Voltage VL in the circuit when Vs < 0 where D is an ideal diode. (Take R1 = Rs = RL = 1 Ω)

View solution

Q. For the amplifier in figure, β = 800. The mid-band voltage gain V0/Vi is

View solution

Q. In the circuit of figure, v0 =

View solution

Q. The bandwidth of an amplifier is BW, of n-stage of such as amplifier are cascaded, the bandwidth will become

View solution

Q. The voltage eo indicated in the figure has been measured by an ideal voltmeter. Which of the following can be calculated?

View solution

Q. The circuit of figure is

View solution