Question
a.
\(q_1=q_2=\frac{2πkb(H-h)}{log_e \frac{R^2}{rB}} \)
b.
\(q_1=q_2=\frac{2πkb(H-h)B}{log_e \frac{r}{R}}\)
c.
\(q_1=q_2=\frac{2πkb(H-h)}{log_e \frac{RB}{r}}\)
d.
\(q_1=q_2=\frac{kb(H-h)}{log_e \frac{R}{rB}} \)
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