Question

Based on the equal deflection criterion, the expression for the equivalent wheel load Pₑ is _________

a.

\(F_e \sqrt{P_e}=(F_1+F_2)\sqrt{P} \)

b.

\(F_e \sqrt{P_e}=(F_1-F_2) \sqrt{P}\)

c.

\(F_e \sqrt{P_e}=(F_1*F_2) \sqrt{P}\)

d.

\(F_e \sqrt{P_e}=(F_1/F_2) \sqrt{P}\)

Posted under Foundation Engineering

Answer: (a).\(F_e \sqrt{P_e}=(F_1+F_2)\sqrt{P} \)

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Q. Based on the equal deflection criterion, the expression for the equivalent wheel load Pₑ is _________

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