Electronic Instruments MCQs

Welcome to our comprehensive collection of Multiple Choice Questions (MCQs) on Electronic Instruments, a fundamental topic in the field of Electrical Measurement and Instrumentation. Whether you're preparing for competitive exams, honing your problem-solving skills, or simply looking to enhance your abilities in this field, our Electronic Instruments MCQs are designed to help you grasp the core concepts and excel in solving problems.

In this section, you'll find a wide range of Electronic Instruments mcq questions that explore various aspects of Electronic Instruments problems. Each MCQ is crafted to challenge your understanding of Electronic Instruments principles, enabling you to refine your problem-solving techniques. Whether you're a student aiming to ace Electrical Measurement and Instrumentation tests, a job seeker preparing for interviews, or someone simply interested in sharpening their skills, our Electronic Instruments MCQs are your pathway to success in mastering this essential Electrical Measurement and Instrumentation topic.

Note: Each of the following question comes with multiple answer choices. Select the most appropriate option and test your understanding of Electronic Instruments. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

So, are you ready to put your Electronic Instruments knowledge to the test? Let's get started with our carefully curated MCQs!

Electronic Instruments MCQs | Page 15 of 16

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Q141.
Voltage across the shunt is measured by ________

a.

voltmeter

b.

multimeter

c.

thermocouple

d.

thermometer

Discuss
Answer: (c).thermocouple
Q142.
Inductance of the coil is ________

a.

L = \(\frac{1}{(2πf)C}\)

b.

L = \(\frac{1}{(2πf)^2}\)

c.

L = \(\frac{1}{C}\)

d.

L = \(\frac{1}{(2πf)^2 C}\)

Discuss
Answer: (d).L = \(\frac{1}{(2πf)^2 C}\)
Q143.
Q meter operator is the principle of __________

a.

Series resonance

b.

Current resonance

c.

Self-inductance

d.

Eddy currents

Discuss
Answer: (a).Series resonance
Q144.
In a Q Meter, the values of tuning capacitor are C₃ and C₄ for resonant frequencies f₃ and 2f₄ respectively. The value of distributed capacitance is?

a.

\(\frac{C_3-C_4}{2}\)

b.

\(\frac{C_3-2C_4}{3}\)

c.

\(\frac{C_3-4C_4}{3}\)

d.

\(\frac{C_3-3C_4}{2}\)

Discuss
Answer: (c).\(\frac{C_3-4C_4}{3}\)
Q145.
A circuit tuned to a frequency of 1.5 MHz and having an effective capacitance of 150 pF. In this circuit, the current falls to 70.7 % of its resonant value. The frequency deviates from the resonant frequency by 5 kHz. Q factor is?

a.

50

b.

100

c.

150

d.

200

Discuss
Answer: (c).150
Q146.
A circuit tuned to a frequency of 1.5 MHz and having an effective capacitance of 150 pF. In this circuit, the current falls to 70.7 % of its resonant value. The deviates from the resonant frequency are 5 kHz. Effective resistance of the circuit is?

a.

2 Ω

b.

3 Ω

c.

5.5 Ω

d.

4.7 Ω

Discuss
Answer: (d).4.7 Ω
Q147.
Q Meter is used to measure _________

a.

Q factor of an inductive coil

b.

Only the effective resistance

c.

Only bandwidth

d.

Q factor of an inductive coil, the effective resistance, and bandwidth

Discuss
Answer: (d).Q factor of an inductive coil, the effective resistance, and bandwidth
Q148.
Q factor of a coil measured by the Q Meter is _________ the actual Q of the coil.

a.

Equal to

b.

Same but somewhat lesser than

c.

Same but somewhat higher than

d.

Not equal to

Discuss
Answer: (b).Same but somewhat lesser than
Q149.
Consider a circuit consisting of two capacitors C₁ and C₂. Let R be the resistance and L be the inductance which are connected in series. Let Q₁ and Q₂ be the quality factor for the two capacitors. While measuring the Q value by the Series Connection method, the value of the Q factor is?

a.

Q = \(\frac{(C_1 – C_2 ) Q_1 Q_2}{Q_1 C_1 – Q_2 C_2}\)

b.

Q = \( \frac{(C_2 – C_1 ) Q_1 Q_2}{Q_1 C_1 – Q_2 C_2}\)

c.

Q = \( \frac{(C_1 – C_2 ) Q_1 Q_2}{Q_2 C_2 – Q_1 C_1}\)

d.

Q = \( \frac{(C_2 – C_1 ) C_1 C_2}{Q_1 C_1 – Q_2 C_2}\)

Discuss
Answer: (a).Q = \(\frac{(C_1 – C_2 ) Q_1 Q_2}{Q_1 C_1 – Q_2 C_2}\)
Q150.
Consider a circuit consisting of two capacitors C₁ and C₂. Let R be the resistance and L be the inductance which are connected in series. Let Q₁ and Q₂ be the quality factor for the two capacitors. While measuring the Q value by the Parallel Connection method, the value of the Q factor is?

a.

Q = \(\frac{(C_1 – C_2 ) Q_1 Q_2}{Q_1 C_1 – Q_2 C_2}\)

b.

Q = \(\frac{(C_2 – C_1 ) Q_1 Q_2}{Q_1 C_1 – Q_2 C_2}\)

c.

Q = \(\frac{(C_1 – C_2 ) Q_1 Q_2}{Q_2 C_2 – Q_1 C_1}\)

d.

Q = \(\frac{(C_2 – C_1 ) C_1 C_2}{Q_1 C_1 – Q_2 C_2}\)

Discuss
Answer: (b).Q = \(\frac{(C_2 – C_1 ) Q_1 Q_2}{Q_1 C_1 – Q_2 C_2}\)
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