Microprocessors MCQs
Welcome to our comprehensive collection of Multiple Choice Questions (MCQs) on Microprocessors, a fundamental topic in the field of Electronics and Communication Engineering. Whether you're preparing for competitive exams, honing your problem-solving skills, or simply looking to enhance your abilities in this field, our Microprocessors MCQs are designed to help you grasp the core concepts and excel in solving problems.
In this section, you'll find a wide range of Microprocessors mcq questions that explore various aspects of Microprocessors problems. Each MCQ is crafted to challenge your understanding of Microprocessors principles, enabling you to refine your problem-solving techniques. Whether you're a student aiming to ace Electronics and Communication Engineering tests, a job seeker preparing for interviews, or someone simply interested in sharpening their skills, our Microprocessors MCQs are your pathway to success in mastering this essential Electronics and Communication Engineering topic.
Note: Each of the following question comes with multiple answer choices. Select the most appropriate option and test your understanding of Microprocessors. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!
So, are you ready to put your Microprocessors knowledge to the test? Let's get started with our carefully curated MCQs!
Microprocessors MCQs | Page 5 of 59
Discover more Topics under Electronics and Communication Engineering
Reason (R): 8085 has only 3 addressing modes.
Reason (R): For frequency stability crystal oscillator is preferred.
X = 2.57
X = (X + 0.06) * 10
I = TRUNC (X)
X = I
X = X / 10.0
The final value of X would be
1. The first letter of a Java variable is lower case.
2. Each successive word in Java variable begins with a capital letter.
3. All other letters are lower case.
4. A Java variable can have a digit as first character.
Which of the above are correct?
IF (JCOKE - 3 * LPEPSI) 5, 6, 7
5 JCOKE = JCOKE + 5
6 JCOKE = JCOKE + 8
7 JCOKE = JCOKE + 11
The value of JCOKE after the execution of above statement will be