Non Uniform Flow in Channels MCQs

Welcome to our comprehensive collection of Multiple Choice Questions (MCQs) on Non Uniform Flow in Channels, a fundamental topic in the field of Fluid Mechanics. Whether you're preparing for competitive exams, honing your problem-solving skills, or simply looking to enhance your abilities in this field, our Non Uniform Flow in Channels MCQs are designed to help you grasp the core concepts and excel in solving problems.

In this section, you'll find a wide range of Non Uniform Flow in Channels mcq questions that explore various aspects of Non Uniform Flow in Channels problems. Each MCQ is crafted to challenge your understanding of Non Uniform Flow in Channels principles, enabling you to refine your problem-solving techniques. Whether you're a student aiming to ace Fluid Mechanics tests, a job seeker preparing for interviews, or someone simply interested in sharpening their skills, our Non Uniform Flow in Channels MCQs are your pathway to success in mastering this essential Fluid Mechanics topic.

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Non Uniform Flow in Channels MCQs | Page 6 of 13

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Q51.
What is the hydraulic radius for a wide rectangular channel section?

a.

3y

b.

2y

c.

y

d.

y/2

Discuss
Answer: (c).y
Q52.
Which of the following equations is true for a wide rectangular channel?

a.

\(\frac{dy}{dx} = S_0 \frac{(1-(\frac{y}{y_n})^3)}{1-(\frac{y}{y_c})^3}\)

b.

\(\frac{dy}{dx} = S_0 \frac{(1-(\frac{y}{y_n})^3)}{1-(\frac{y_c}{y})^3}\)

c.

\(\frac{dy}{dx} = S_0 \frac{(1-(\frac{y_n}{y})^3)}{1-(\frac{y_c}{y})^3}\)

d.

\(\frac{dy}{dx} = S_0 \frac{(1-(\frac{y_n}{y})^3)}{1-(\frac{y}{y_c})^3}\)

Discuss
Answer: (c).\(\frac{dy}{dx} = S_0 \frac{(1-(\frac{y_n}{y})^3)}{1-(\frac{y_c}{y})^3}\)
Q53.
Calculate the rate of change of depth of a wide rectangular channel having uniform flow depth of 2m and the depth during GVF is 1.5m. Given:yc=1m, S₀=1 in 1500.

a.

1.4×10⁻⁴m

b.

2.4×10⁻⁴m

c.

3.4×10⁻⁴m

d.

4.4×10⁻⁴m

Discuss
Answer: (d).4.4×10⁻⁴m
Q54.
Which of the following equations is true considering Chezy’s equation?

a.

\(\frac{S_0}{S_f} = (\frac{y_n}{y})^3\)

b.

\(\frac{S_0}{S_f} = (\frac{y}{y_n})^3\)

c.

\(\frac{S_f}{S_0} = (\frac{y_n}{y})^3\)

d.

\(\frac{S_f}{S_0} = (\frac{y_n}{y})^3\)

Discuss
Answer: (d).\(\frac{S_f}{S_0} = (\frac{y_n}{y})^3\)
Q55.
Which of the following equations is true considering Manning’s equation?

a.

\(\frac{S_f}{S_0} = (\frac{y_n}{y})^{\frac{10}{3}}\)

b.

\(\frac{S_f}{S_0} = (\frac{y}{y_n})^{\frac{10}{3}}\)

c.

\(\frac{S_0}{S_f} = (\frac{y}{y_n})^{\frac{10}{3}}\)

d.

\(\frac{S_0}{S_f} = (\frac{y_n}{y})^{\frac{10}{3}}\)

Discuss
Answer: (a).\(\frac{S_f}{S_0} = (\frac{y_n}{y})^{\frac{10}{3}}\)
Q56.
The slope of the energy line of a wide rectangular channel is 4×10⁻⁵ and the bed slope of the channel is 1 in 1200 using manning’s equation, calculate the depth in GVF if the uniform depth of flow is 1.5m.

a.

0.5m

b.

0.6m

c.

0.7m

d.

0.8m

Discuss
Answer: (b).0.6m
Q57.
The value of slope of energy line of a wide rectangular channel is 3×10⁻⁴ and the bed slope of the channel is 1 in 1500 using chezy’s equation, calculate the uniform flow depth if the depth during GVF is 2m.

a.

1.61m

b.

2.61m

c.

3.61m

d.

4.61m

Discuss
Answer: (b).2.61m
Q58.
If y = 2m and velocity of flow is 2.5m⁄s, calculate the critical depth.

a.

0.36m

b.

1.36m

c.

2.36m

d.

3.36m

Discuss
Answer: (b).1.36m
Q59.
Which of the following expressions is true?

a.

\(\frac{dy}{dx} = S_0 \frac{((\frac{y}{y_n})^3-1)}{1-(\frac{y}{y_c})^3}\)

b.

\(\frac{dy}{dx} = S_0 \frac{(1-(\frac{y}{y_n})^3)}{1-(\frac{y}{y_c})^3}\)

c.

\(\frac{dy}{dx} = S_0 \frac{(1-(\frac{y_n}{y})^3)}{1-(\frac{y}{y_c})^3}\)

d.

\(\frac{dy}{dx} = S_0 \frac{(\frac{y_n}{y})-1}{1-(\frac{y}{y_c})^3}\)

Discuss
Answer: (a).\(\frac{dy}{dx} = S_0 \frac{((\frac{y}{y_n})^3-1)}{1-(\frac{y}{y_c})^3}\)
Q60.
Which of the following expressions is true?

a.

\(\frac{dy}{dx} = S_0 \frac{((\frac{y}{y_n})^{\frac{10}{3}}-1)}{1-(\frac{y}{y_c})^3}\)

b.

\(\frac{dy}{dx} = S_0 \frac{(1-(\frac{y}{y_n})^{\frac{10}{3}})}{1-(\frac{y}{y_c})^3}\)

c.

\(\frac{dy}{dx} = S_0 \frac{(1-(\frac{y_n}{y})^{\frac{10}{3}})}{1-(\frac{y}{y_c})^3}\)

d.

\(\frac{dy}{dx} = S_0 \frac{(\frac{y_n}{y})-1}{1-(\frac{y}{y_c})^3}\)

Discuss
Answer: (a).\(\frac{dy}{dx} = S_0 \frac{((\frac{y}{y_n})^{\frac{10}{3}}-1)}{1-(\frac{y}{y_c})^3}\)
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