Elements of Elasticity and Stress Distribution MCQs

Welcome to our comprehensive collection of Multiple Choice Questions (MCQs) on Elements of Elasticity and Stress Distribution, a fundamental topic in the field of Geotechnical Engineering. Whether you're preparing for competitive exams, honing your problem-solving skills, or simply looking to enhance your abilities in this field, our Elements of Elasticity and Stress Distribution MCQs are designed to help you grasp the core concepts and excel in solving problems.

In this section, you'll find a wide range of Elements of Elasticity and Stress Distribution mcq questions that explore various aspects of Elements of Elasticity and Stress Distribution problems. Each MCQ is crafted to challenge your understanding of Elements of Elasticity and Stress Distribution principles, enabling you to refine your problem-solving techniques. Whether you're a student aiming to ace Geotechnical Engineering tests, a job seeker preparing for interviews, or someone simply interested in sharpening their skills, our Elements of Elasticity and Stress Distribution MCQs are your pathway to success in mastering this essential Geotechnical Engineering topic.

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Elements of Elasticity and Stress Distribution MCQs | Page 16 of 19

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Q151.
The rate of change of velocity along the depth of layer is ___________

a.

\(\frac{βˆ‚v}{βˆ‚z}=\frac{1}{Ξ³_w}\frac{βˆ‚^2 \overline{u}}{βˆ‚z^2}\)

b.

\(\frac{βˆ‚v}{βˆ‚z}=\frac{k}{Ξ³_w}\frac{\overline{u}}{βˆ‚z^2} \)

c.

\(\frac{βˆ‚v}{βˆ‚z}=\frac{βˆ‚^2\overline{u}}{βˆ‚z^2}\)

d.

\(\frac{βˆ‚v}{βˆ‚z}=\frac{k}{Ξ³_w}\frac{βˆ‚^2 \overline{u}}{βˆ‚z^2}\)

Discuss
Answer: (d).\(\frac{βˆ‚v}{βˆ‚z}=\frac{k}{Ξ³_w}\frac{βˆ‚^2 \overline{u}}{βˆ‚z^2}\)
Q152.
_________ chart is used to find the vertical stress on Westergaard’s equation.

a.

Influence chart

b.

Isocurve chart

c.

Isobar chart

d.

Fenske’s chart

Discuss
Answer: (a).Influence chart
Q153.
_________ is more accurate method of determining the vertical stress at any point.

a.

Isobar chart

b.

equivalent point load method

c.

Influence chart

d.

Fenske’s chart

Discuss
Answer: (c).Influence chart
Q154.
The Newmark’s influence chart consists of _________

a.

a single circle only

b.

a number of circles and radiating lines

c.

bar diagram

d.

small rectangular unit areas

Discuss
Answer: (b).a number of circles and radiating lines
Q155.
If a uniformly loaded circular area is divided into 20 sectors, then the influence value if is given by ___________

a.

\(\frac{1}{20}\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right]\)

b.

\(20\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right]\)

c.

\(20\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{5}{2}\right]\)

d.

\(\frac{1}{20}\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{5}{2} \right]\)

Discuss
Answer: (a).\(\frac{1}{20}\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right]\)
Q156.
If the influence value \(i_f=\frac{1}{35} \left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right] \) for a uniformly loaded circular area, then the circular area is divided into _________ sectors.

a.

20

b.

35

c.

7

d.

14

Discuss
Answer: (b).35
Q157.
If a uniformly loaded circular area is divided into 44 sectors, then the influence value if is given by ___________

a.

\(\frac{1}{44} \left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right] \)

b.

\(44\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right] \)

c.

\(44\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{5}{2}\right] \)

d.

\(\frac{1}{44} \left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{5}{2}\right] \)

Discuss
Answer: (a).\(\frac{1}{44} \left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right] \)
Q158.
In Newmark’s influence chart method, the point below which pressure is required should lie within the loaded area.

a.

True

b.

False

c.

May be True or False

d.

Can't say

Discuss
Answer: (b).False
Q159.
The vertical stress under the corner of a uniformly loaded rectangular area of size a, b at depth z and m=a/z, n=b/z is given by ___________

a.

\(Οƒ_z=\frac{2q’}{Ο€z}\frac{1}{\left[1+(\frac{x}{z})^2\right]^2}\)

b.

\(Οƒ_z=\frac{q}{4Ο€} \left[\frac{2mn\sqrt{(m^2+n^2+1)}}{m^2+n^2+m^2 n^2+1}\right] \)

c.

\(Οƒ_z=\frac{q}{4Ο€} \left[\frac{2mn\sqrt{(m^2+n^2+1)}}{m^2+n^2+m^2 n^2+1}* \frac{m^2+n^2+2}{m^2+n^2+1}+tan^{-1}⁑\frac{2mn\sqrt{(m^2+n^2+1)}}{m^2+n^2+m^2 n^2+1} \right] \)

d.

\(Οƒ_z=q\left[1-\left[\frac{1}{1+(\frac{a}{z})^2}\right]^\frac{3}{2}\right] \)

Discuss
Answer: (c).\(Οƒ_z=\frac{q}{4Ο€} \left[\frac{2mn\sqrt{(m^2+n^2+1)}}{m^2+n^2+m^2 n^2+1}* \frac{m^2+n^2+2}{m^2+n^2+1}+tan^{-1}⁑\frac{2mn\sqrt{(m^2+n^2+1)}}{m^2+n^2+m^2 n^2+1} \right] \)
Q160.
The vertical stress under the corner of a uniformly loaded rectangular area of size 2m*4m at depth 5m and load of 80 kN/m² is given by ___________

a.

6.22 kN/m²

b.

7.45 kN/m²

c.

8.12 kN/m²

d.

9.23 kN/m²

Discuss
Answer: (b).7.45 kN/m²
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