Question
a.
Fe ==> Fe⁺² + 2e, 2H⁺ + 2e ==> H₂
b.
Fe ==> Fe⁺² + 2e, O₂ + 2H₂O + 4e ==> 4OH⁻
c.
Fe⁺² + 2e ==> Fe⁺², 4H⁺ + O₂ + 4e ==> 2H₂O
d.
Fe⁺² + 2e ==> Fe⁺², 2H⁺ + 2e ==> H₂
Posted under Corrosion Engineering
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