Question

9548 + 7314 = 8362 + (?)

a.

8230

b.

8410

c.

8500

d.

8600

Posted under Aptitude

Answer: (c).8500

Interact with the Community - Share Your Thoughts

Uncertain About the Answer? Seek Clarification Here.

Understand the Explanation? Include it Here.

Q. 9548 + 7314 = 8362 + (?)

Similar Questions

Explore Relevant Multiple Choice Questions (MCQs)

Q. In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 35 as quotient. What is the correct quotient ?

Q. 2 + 2^2 + 2^3 + ... + 2^9 = ?

Q. The sum of even numbers between 1 and 31 is:

Q. If the number 91876 * 2 is completely divisible by 8, then the smallest whole number in place of * will be:

Q. 2056 x 987 = ?

Q. On multiplying a number by 7, the product is a number each of whose digits is 3. The smallest such number is:

Q. If 60% of 3/5 of a number is 36, then the number is:

Q. If x and y are the two digits of the number 653xy such that this number is divisible by 80, then x + y = ?

Q. The difference of the squares of two consecutive odd integers is divisible by which of the following integers ?

Q. What is the unit digit in (4137)^754?

Q. 587 x 999 = ?

Q. A number was divided successively in order by 4, 5 and 6. The remainders were respectively 2, 3 and 4. The number is:

Q. If (64)^2 - (36)^2 = 20 * x, then x = ?

Q. Which one of the following can't be the square of natural number ?

Q. (2^2 + 4^2 + 6^2 + ... + 20^2) = ?

Q. 35 + 15 x 1.5 = ?

Q. 666 ÷ 6 ÷ 3 = ?

Q. The sum of all two digit numbers divisible by 5 is:

Q. The difference between the place values of two sevens in the numeral 69758472 is

Q. On dividing a number by 68, we get 269 as quotient and 0 as remainder. On dividing the same number by 67, what will the remainder ?

Recommended Subjects

Are you eager to expand your knowledge beyond Aptitude? We've handpicked a range of related categories that you might find intriguing.

Click on the categories below to discover a wealth of MCQs and enrich your understanding of various subjects. Happy exploring!