Q. In the circuit of figure the current through L at t = ∞ is

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Q. Current having waveform in figure flows through 10 Ω resistance. Average power is

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Q. S is closed for a long time and steady state is reached. S is opened at t(0-). The voltage marked V is V0 at t = 0+ and Vf at t = ∞. Then value of V0 and Vf are respectively

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Q. The switch in figure is initially closed. At t = 0 the switch is opened. At t = 0+, the current through inductance is

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Q. The resonant frequency of the circuit shown in figure is

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Q. For the circuit shown in the figure, the time constant RC = 1 ms. The input voltage is V1(t) = √2 sin 10³ t. The output voltage V0(t) is equal to

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Q. Flux linkages ψ and voltages v are related as

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Q. Calculate i(t) for t ≥ 0, assuming the switch has been in position A for a long time at t = 0, the switch is moved to position B

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Q. In figure, capacitor is uncharged. The switch is closed at t = 0 at t = 0+ di/dt is

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Q. In figure the total inductance of the circuit is

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Q. In the network of figure, the voltage drops across R1, R2, R3 are 6 V, 8 V and 12 V with polarities as shown. The value of R3 is

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Q. In figure which is correct at any time t

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Q. In figure, the magnitude of V

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Q. The driving point impedance of a network is given by following equation. The number of energy storing elements in the network is

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Q. The following differential equation has

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Q. If the transmission parameters of the given networks are A = C = 1, B = 2 and D = 3, then the value of Zm is

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Q. In figure, the current through 10 V battery is

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Q. The switch in figure is initially closed. At t = 0 the switch is opened. At t = 0+, the current through R is

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Q. The power dissipated in 4 Ω resistance in figure is

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Q. In the network of the figure is the maximum power is delivered to RL if its value is

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