Question

For the following expression, the correct Pascal equivalent is

a.

BETA * JCOS (OMEGA * T + THETA) / SQRT (SQR (BETA) + SQR (OMEGA))

b.

BETA COS (OMEGA * T + THETA) / SQRT [SQR (BETA) + SQR (OMEGA)]

c.

BETA COS (OMEGA T + THETA) / SQRT [SQR (BETA) + SQR (OMEGA)]

d.

None of the above

Posted under Electronics and Communication Engineering

Answer: (a).BETA * JCOS (OMEGA * T + THETA) / SQRT (SQR (BETA) + SQR (OMEGA))

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