Question

The Laplace transform of exp(at), where a > 0, is defined only for the Laplace parameter, s > a since

a.

the function is exponential.

b.

the Laplace transform of integral of exp(at) has finite values only for s > a.

c.

the Laplace transform integral of exp(at) has initial values only for s > a.

d.

the function exp(at) is piece-wise continuous only for s > a.

Answer: (b).the Laplace transform of integral of exp(at) has finite values only for s > a.

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Q. The Laplace transform of exp(at), where a > 0, is defined only for the Laplace parameter, s > a since

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