Question

According to combination rule, if the total number of outcomes are 'r' and distinct outcome collection is 'n' then combinations are calculated as

a.

n! ⁄ r!(n - r)!

b.

n! ⁄ r!(n + r)!

c.

r! ⁄ n!(n - r)!

d.

r! ⁄ n!(n + r)!

Answer: (a).n! ⁄ r!(n - r)!

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Q. According to combination rule, if the total number of outcomes are 'r' and distinct outcome collection is 'n' then combinations are calculated as

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