#### Question

K = (1.45 + 0.5 * 10¯⁵ t²) KJ/m hr deg

Where, t is the temperature in degree centigrade. Calculate the heat loss per square meter of the wall surface area?

a.

1355.3 kJ/m² hr

b.

2345.8 kJ/m² hr

c.

1745.8 kJ/m² hr

d.

7895.9 kJ/m² hr

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###### Q. The inner and outer surfaces of a furnace wall, 25 cm thick, are at 300 degree Celsius and 30 degree Celsius. Here thermal conductivity is given by the relation K = (1.45 + 0.5 *...

###### Darshan : September 05, 2023

The inner and outer surfaces of furnace wall, 25 cm thick, are at 300°C and 30°C

respectively. Relation for thermal conductivity given below

k = (1.45+(0.5 x 10-5 t2) KJ/m-hr-deg

Where,

t is temperature in centigrade

Calculate heat loss per square meter of the wall surface area

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