Q. In period 3, metal that has the highest electronegativity is

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Q. Consider the reaction: SiCl₄(l) + 2H₂O(l) → SiO₂(s) + HCl. The form of HCl produced in this reaction is

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Q. Upon hydration of Al₂Cl₆, Al⁺³ is formed, and the solution becomes

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Q. The oxidation number of Na in NaCl is

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Q. The oxidation number of Al in Al₂Cl₆ is

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Q. Ionic Chlorides of which of these do not react with water

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Q. Without water, aluminum chloride exists as

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Q. Ionic Chlorides of which of these do not react with water

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Q. The oxidation number of S in SCl₂ is

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Q. The oxidation number of P in PCl₅ is

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Q. SiO₂ is formed after the reaction of SiCl₄(l) + 2H₂O(l). What is the state of SiO₂?

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Q. The oxidation number of Phosphorus (P) in Phosphorus Chloride (PCl₃) is

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Q. The oxidation number of Magnesium (Mg) in Magnesium Chloride (MgCl₂) is

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Q. The elements in which the outermost electrons are in the same principal quantum shell form the

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Q. Hydrated Aluminum Chloride (AlCl₃) exists as

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Q. Another product of the reaction SiO₂(s) + NaOH(l) → Na₂SiO₃(aq) would be

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Q. Oxygen has a higher electronegativity than

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Q. Consider the reaction: Al₂O₃+NaOH + H₂O (l) → NaAl(OH)₄ (aq). The moles of NaOH required to balance the equation are

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Q. Metal chloride that is hydrolyzed is

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Q. Consider the reaction: P₄O₁₀(s) + H₂O (l) → H₃PO₄ (aq). The moles of H₂O required to balance equation will be

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