Enzyme Kinetics Fundamentals MCQs

Welcome to our comprehensive collection of Multiple Choice Questions (MCQs) on Enzyme Kinetics Fundamentals, a fundamental topic in the field of Enzyme Technology. Whether you're preparing for competitive exams, honing your problem-solving skills, or simply looking to enhance your abilities in this field, our Enzyme Kinetics Fundamentals MCQs are designed to help you grasp the core concepts and excel in solving problems.

In this section, you'll find a wide range of Enzyme Kinetics Fundamentals mcq questions that explore various aspects of Enzyme Kinetics Fundamentals problems. Each MCQ is crafted to challenge your understanding of Enzyme Kinetics Fundamentals principles, enabling you to refine your problem-solving techniques. Whether you're a student aiming to ace Enzyme Technology tests, a job seeker preparing for interviews, or someone simply interested in sharpening their skills, our Enzyme Kinetics Fundamentals MCQs are your pathway to success in mastering this essential Enzyme Technology topic.

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Enzyme Kinetics Fundamentals MCQs | Page 5 of 6

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Q41.
The following rate equation represents _____________ inhibition.

\(V=\frac{V_{max} [S]}{K_m (1+\frac{I}{K_i})+[S]}\)
Discuss
Answer: (a).competitive
Q42.
Uncompetitive inhibition is most noticeable at low substrate concentration and can be overcome at high substrate concentration.
Discuss
Answer: (b).False
Q43.
Inhibition of invertase by sucrose falls into which category of inhibition?
Discuss
Answer: (a).Substrate inhibition
Q44.
______________ inhibition represent the following rate equation.

\(V=\frac{\left (\frac{V_{max}}{1+\frac{[I]}{K_i}}\right )[S]}{K_m+[S]}\)
Discuss
Answer: (d).Non-competitive inhibition
Q45.
The __________ inhibition gives the following rate equation.

\(V=\frac{V_{max} [S]}{K_m+[S](1+\frac{[S]}{K_s})}\)
Discuss
Answer: (a).Substrate
Discuss
Answer: (b).Vโ‚˜โ‚โ‚“ is unchanged and Kโ‚˜ increases 2Kโ‚˜
Discuss
Answer: (d).Lowers to 0.67 Vโ‚˜โ‚โ‚“ and Kโ‚˜ increases to 2Kโ‚˜
Discuss
Answer: (a).Lowers to 0.5 Vโ‚˜โ‚โ‚“ and 0.5 Kโ‚˜
Discuss
Answer: (c).Lowers to 0.5 Vโ‚˜โ‚โ‚“ and Kโ‚˜ remains unchanged
Q50.
Mercury causes irreversible inhibition.
Discuss
Answer: (a).True
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