Heat Transfer From Extended Surfaces MCQs

Welcome to our comprehensive collection of Multiple Choice Questions (MCQs) on Heat Transfer From Extended Surfaces, a fundamental topic in the field of Heat Transfer. Whether you're preparing for competitive exams, honing your problem-solving skills, or simply looking to enhance your abilities in this field, our Heat Transfer From Extended Surfaces MCQs are designed to help you grasp the core concepts and excel in solving problems.

In this section, you'll find a wide range of Heat Transfer From Extended Surfaces mcq questions that explore various aspects of Heat Transfer From Extended Surfaces problems. Each MCQ is crafted to challenge your understanding of Heat Transfer From Extended Surfaces principles, enabling you to refine your problem-solving techniques. Whether you're a student aiming to ace Heat Transfer tests, a job seeker preparing for interviews, or someone simply interested in sharpening their skills, our Heat Transfer From Extended Surfaces MCQs are your pathway to success in mastering this essential Heat Transfer topic.

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Heat Transfer From Extended Surfaces MCQs | Page 2 of 8

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Q11.
In heat dissipation from an infinitely long fin, the boundary conditions are

a.

t = t0 at x = infinity and t = ta at x = 0

b.

t = t0 at x = 0 and t = ta at x = infinity

c.

t = t0 at x = 0 and t = ta at x = 0

d.

t = t0 at x = infinity and t = ta at x = infinity

Discuss
Answer: (b).t = t0 at x = 0 and t = ta at x = infinity
Q12.
The temperature distribution in case of infinitely long fin is

a.

t – t a/t₀ – t a = mx

b.

t – t a/t₀ – t a = -mx

c.

t – t a/t₀ – t a = e-m x

d.

t – t a/t₀ – t a = log (m x)

Discuss
Answer: (c).t – t a/t₀ – t a = e-m x
Q13.
The rate of heat transfer in case of infinitely long fin is given by

a.

(h P k A)^1/2 (t₀ – t a)

b.

(h P A)^1/2 (t₀ – t a)

c.

(P k A)^1/2 (t₀ – t a)

d.

(h k A)^1/2 (t₀ – t a)

Discuss
Answer: (a).(h P k A)^1/2 (t₀ – t a)
Q14.
Let us say there are two rods having same dimensions, one made of brass (k = 85W/m K) and the other of copper (k = 375W/m K), having one of their ends inserted into a furnace. At a section 10.5 cm away from the furnace, the temperature of brass rod is 120 degree Celsius. Find the distance at which the same temperature would be reached in the copper rod? Both ends are exposed to the same environment

a.

12.54 cm

b.

45.87 cm

c.

12.34 cm

d.

22.05 cm

Discuss
Answer: (d).22.05 cm
Q15.
Three rods, one made of silver (l = 420W/m K), second made of aluminum (k = 210W/m K) and the third made of iron (k = 70W/m K) are coated with a uniform layer of wax all around. The rods are placed vertically in a boiling water bath with 250 mm length of each rod projecting outside. If all the rods are having following dimensions i.e. diameter = 15 mm and length = 300 mm and have identical surface coefficient 12.5W/ m² K, work out the ratio of lengths up to which wax will melt on each rod

a.

2.45:1:1.732

b.

1.732:1:2.45

c.

2.45:1.732:1

d.

1.732:1:2.45

Discuss
Answer: (c).2.45:1.732:1
Q16.
Which fin yields the maximum heat flow per unit weight?

a.

Straight triangular fin

b.

Curved triangular fin

c.

Parabolic fin

d.

Hyperbolic fin

Discuss
Answer: (a).Straight triangular fin
Q17.
Heat dissipation by every segment of the fin is

a.

Sometimes same

b.

Same

c.

Not same

d.

Sometimes same or sometimes not same

Discuss
Answer: (c).Not same
Q18.
“If a fin of a constant cross section is used, there would be wastage of material”. Chose the correct option.

a.

True

b.

False

c.

May be

d.

Can't say

Discuss
Answer: (a).True
Q19.
Which one is true regarding parabolic fin?

a.

It dissipates the minimum amount of heat at minimum material cost

b.

It dissipates the minimum amount of heat at maximum material cost

c.

It dissipates the maximum amount of heat at maximum material cost

d.

It dissipates the maximum amount of heat at minimum material cost

Discuss
Answer: (d).It dissipates the maximum amount of heat at minimum material cost
Q20.
For parabolic fin, the curve follows which law?

a.

y = C/x^2

b.

y = C x^4

c.

y = C x^2

d.

y = C x^(1/2)

Discuss
Answer: (c).y = C x^2
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