Discussion Forum
Que.  The inner and outer surfaces of a furnace wall, 25 cm thick, are at 300 degree Celsius and 30 degree Celsius. Here thermal conductivity is given by the relation
K = (1.45 + 0.5 * 10¯⁵ t²) KJ/m hr deg Where, t is the temperature in degree centigrade. Calculate the heat loss per square meter of the wall surface area? 
a.  1355.3 kJ/m² hr 
b.  2345.8 kJ/m² hr 
c.  1745.8 kJ/m² hr 
d.  7895.9 kJ/m² hr 
Correct Answer:1745.8 kJ/m² hr
