Q. A solid cylinder of 15 cm diameter and 40 cm long, consists of two parts made of different materials. The first part at the base is 1.5 cm long and of specific gravity=6.5. The other part of the cylinder is made of the material having specific gravity 0.75. State, if the it can float vertically in water.

View solution

Q. A solid cylinder of diameter 5.0 m has a height of 6.0 m. Find the meta-centric height of the cylinder if the specific gravity of the material of cylinder 0.45 and it is floating in water with its axis vertical.

View solution

Q. The principle of floatation of bodies is based on the premise of

View solution

Q. Meta centre always lies below the centre of gravity

View solution

Q. or a completely immersed body, the metacentric height is always zero.

View solution

Q. The metacentric height is affected by the change in density.

View solution

Q. Proper explanation for metacentre is:

View solution

Q. In case of spherically shaped bodies of uniform mass distribution and completely immersed in fluid and floating, the centre of buoyancy coincides with centre of gravity.

View solution

Q. A solid cylinder of diameter 4.5 has a height of 2.5 metres. Find the meta-centric height of the cylinder when it is floating in water with its axis vertical. The sp. gr. of the cylinder=0.45.

View solution

Q. A block of material of specific gravity 0.45 floats in water. Determine the meta-centric height of the block if its size is 3 m * 2 m* 0.8 m.

View solution

Q. A uniform body of size 4 m long * 2.5 m wide * 1.5 m deep floats in water. What is the weight of the body if depth of immersion is 1 m ?

View solution

Q. A rectangular pontoon is 5 m long, 3 m wide and 1.40 m high. The depth of immersion of the pontoon is 0.60 m in seawater. If the centre of gravity is 0.7 m above the bottom of the pontoon, determine the metacentric height. The density for seawater = 1045 kg/m³.

View solution

Q. Submarines use principle of ‘neutral buoyancy’ to go into the water.

View solution

Q. As a balloon rises in the air its volume increases, at the end it acquires a stable height and cannot rise any further.

View solution

Q. What happens to the buoyant force acting on the airship as it rises in the air?

View solution

Q. How can relatively denser object be made to float on the less dense fluid?

View solution

Q. What is the principal cause of action of buoyant force on a body submerged partially or fully in fluid?

View solution

Q. Find the density of metallic body which floats at the interface of mercury of sp.gr 13.6 and water such that 40 % of its volume is sub-merged in mercury and 60% in water.

View solution

Q. A body of dimensions 2.7 m * 3.8 m * 2.5 m, weighs 2500 N in water. Find its weight in air.

View solution

Q. A stone weighs 650 N in air and 275 N in water. Compute its specific gravity.

View solution