Q. The oscillator shown in figure is a

View solution

Q. For an I/p of Vs = 5 sin ωt (assuming ideal diode), circuit shown in the figure will behave as a

View solution

Q. In figure

View solution

Q. In a Hartley oscillator the condition for sustained oscillations is hfe = L₁/L₂ . If there exists mutual inductance M between coils L₁ and L₂, then the above condition will get modified as hfe

View solution

Q. Figure shows current pulses of a class C power amplifier. The fundamental frequency of these pulses is

View solution

Q. The Clapp oscillator shown in figure will operate at

View solution

Q. Figure shows a zener circuit and characteristic of the zener used. If R2 is the lowest load resistance, then for proper voltage regulation R1 must be

View solution

Q. In figure, VC is approximately equal to

View solution

Q. Figure shows small signal model of CB amplifier circuit. Then I and R are respectively equal to

View solution

Q. Figure represents a

View solution

Q. In figure VBE = 0.7 V. If base current required to saturate the transistor is 0.1 mA, Vi =

View solution

Q. As per miller theorem the circuit of figure (1) can be replaced by that in figure (2) If V1/V2 = K, then Y1 and Y2 are equal to

View solution

Q. In a biased JFET (Figure) the shape of the channel is as shown because

View solution

Q. In a half wave rectifier, Vrms is

View solution

Q. The approximate value of input impedance of a common emitter amplifier with emitter resistance Re is given by

View solution

Q. The collector voltage VC of the circuit shown in the given figure aside is approximately

View solution

Q. The symbol shown in figure represents a

View solution

Q. Which of the following represents the equivalent circuit of a crystal for crystal oscillator?

View solution

Q. In figure, the function of resistor R is

View solution

Q. The circuit of figure is

View solution