Discussion Forum
Que. | With variable thermal conductivity, Fourier law of heat conduction through a plane wall can be expressed as |
a. | Q = -k0 (1 + β t) A d t/d x |
b. | Q = k0 (1 + β t) A d t/d x |
c. | Q = – (1 + β t) A d t/d x |
d. | Q = (1 + β t) A d t/d x |
Correct Answer:Q = -k0 (1 + β t) A d t/d x
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