Heat Transfer Basics MCQs

Welcome to our comprehensive collection of Multiple Choice Questions (MCQs) on Heat Transfer Basics, a fundamental topic in the field of Basic Chemical Engineering. Whether you're preparing for competitive exams, honing your problem-solving skills, or simply looking to enhance your abilities in this field, our Heat Transfer Basics MCQs are designed to help you grasp the core concepts and excel in solving problems.

In this section, you'll find a wide range of Heat Transfer Basics mcq questions that explore various aspects of Heat Transfer Basics problems. Each MCQ is crafted to challenge your understanding of Heat Transfer Basics principles, enabling you to refine your problem-solving techniques. Whether you're a student aiming to ace Basic Chemical Engineering tests, a job seeker preparing for interviews, or someone simply interested in sharpening their skills, our Heat Transfer Basics MCQs are your pathway to success in mastering this essential Basic Chemical Engineering topic.

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Heat Transfer Basics MCQs | Page 7 of 53

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Q61.
The average heat transfer co-efficient for laminar film condensation on vertical surface is inversely proportional to (where, ฮ”T = Temperature drop across condensate film )

a.

(ฮ”T)²

b.

โˆšฮ”T

c.

(ฮ”T)^1/4

d.

(ฮ”T)^3/2

Discuss
Answer: (c).(ฮ”T)^1/4
Q62.
Bulk of the convective heat transfer resistance from a hot tube surface to the fluid flowing in it, is

a.

in the central core of the fluid.

b.

uniformly distributed throughout the fluid.

c.

mainly confined to a thin film of fluid near the surface.

d.

none of these.

Discuss
Answer: (c).mainly confined to a thin film of fluid near the surface.
Q63.
Which of the following is concerned with both heat and mass transfer ?

a.

Lewis relationship

b.

Nusselt number

c.

Kutateladze number

d.

Froude number

Discuss
Answer: (a).Lewis relationship
Q64.
A backward feed multiple effect evaporator is better than forward feed for concentrating cold feed, because it provides

a.

higher economy

b.

lower capacity

c.

both (a) & (b)

d.

lower economy

Discuss
Answer: (a).higher economy
Q65.
A 10 cm diameter steam pipe, carrying steam at 180°C, is covered with an insulation (conductivity = 0.6 W/m.°C). It losses heat to the surroundings at 30°C. Assume a heat transfer co-efficient of 0.8 W/m².°C for heat transfer from surface to the surroundings. Neglect wall resistance of the pipe and film resistance of steam. If the insulation thickness is 2 cms, the rate of heat loss from this insulated pipe will be

a.

greater than that for uninsulated steam pipe.

b.

less than that of the uninsulated steam pipe.

c.

equal to that of the uninsulated steam pipe.

d.

less than the steam pipe with 5 cms insulation.

Discuss
Answer: (b).less than that of the uninsulated steam pipe.
Q66.
Fouling factor

a.

is a dimensionless quantity.

b.

does not provide a safety factor for design.

c.

accounts for additional resistances to heat flow.

d.

none of these.

Discuss
Answer: (c).accounts for additional resistances to heat flow.
Q67.
In case of vertical tube evaporator, with increase in liquor level, the overall heat transfer co-efficient

a.

increases

b.

decreases

c.

is not affected

d.

may increase or decrease; depends on the feed

Discuss
Answer: (b).decreases
Q68.
The steam ejector is used to

a.

remove condensate from the steam pipelines.

b.

create vacuum.

c.

superheat the steam.

d.

none of these.

Discuss
Answer: (b).create vacuum.
Q69.
For shell and tube heat exchanger, with increasing heat transfer area, the purchased cost per unit heat transfer area

a.

increases

b.

decreases

c.

remains constant

d.

passes through a maxima

Discuss
Answer: (d).passes through a maxima
Q70.
The thermal efficiency of a reversible heat engine operating between two given thermal reservoirs is 0.4. The device is used either as a refrigerator or as a heat pump between the same reservoirs. Then the coefficient of performance as a refrigerator (COP)R and the co-efficient of performance as a heat pump (COP)HP are

a.

(COP)R = (COP)HP = 0.6

b.

(COP)R = 2.5; (COP)HP = 1.5

c.

(COP)R = 1.5; (COP)HP = 2.5

d.

(COP)R = (COP)HP = 2.5

Discuss
Answer: (c).(COP)R = 1.5; (COP)HP = 2.5
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