| 21. | The formula of calculating mean for hyper geometric probability distribution is |
| a. | n (m ⁄ n) |
| b. | m (n ⁄ n) |
| c. | n (n ⁄ m) |
| d. | n (m ⁄ n) |
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Answer: (d).n (m ⁄ n)
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| 22. | The formula in which the binomial distribution approaches normal probability distribution with the help of normal variable is written as |
| a. | x - qn divided by square root of pq |
| b. | x - np divided by square root of npq |
| c. | x + np divided by square root of np |
| d. | x - pq divided by square root of npq |
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Answer: (b).x - np divided by square root of npq
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| 23. | If the value of m in beta distribution is 35 and the value of n in beta distribution is 50 then the expected value of random variable x in beta distribution is |
| a. | 0.411 |
| b. | 0.311 |
| c. | 0.511 |
| d. | 0.211 |
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Answer: (a).0.411
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| 24. | In a negative binomial distribution of probability, the random variable is also classified as |
| a. | discrete random variable |
| b. | continuous waiting time random variable |
| c. | discrete waiting time random variable |
| d. | discrete negative binomial variable |
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Answer: (c).discrete waiting time random variable
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| 25. | The demand of products per day for three days are 21, 19, 22 units and their respective probabilities are 0.29, 0.40, 0.35. The profit per unit is $0.50 then the expected profits for three days are |
| a. | 21, 19, 22 |
| b. | 21.5, 19.5, 22.5 |
| c. | 0.29, 0.40, 0.35 |
| d. | 3.045, 3.8, 3.85 |
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Answer: (d).3.045, 3.8, 3.85
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