Steady State Conduction MCQs

Welcome to our comprehensive collection of Multiple Choice Questions (MCQs) on Steady State Conduction, a fundamental topic in the field of Heat Transfer. Whether you're preparing for competitive exams, honing your problem-solving skills, or simply looking to enhance your abilities in this field, our Steady State Conduction MCQs are designed to help you grasp the core concepts and excel in solving problems.

In this section, you'll find a wide range of Steady State Conduction mcq questions that explore various aspects of Steady State Conduction problems. Each MCQ is crafted to challenge your understanding of Steady State Conduction principles, enabling you to refine your problem-solving techniques. Whether you're a student aiming to ace Heat Transfer tests, a job seeker preparing for interviews, or someone simply interested in sharpening their skills, our Steady State Conduction MCQs are your pathway to success in mastering this essential Heat Transfer topic.

Note: Each of the following question comes with multiple answer choices. Select the most appropriate option and test your understanding of Steady State Conduction. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

So, are you ready to put your Steady State Conduction knowledge to the test? Let's get started with our carefully curated MCQs!

Steady State Conduction MCQs | Page 6 of 7

For the same amount of fabrication material and same inside capacity, the heat loss is lowest in
Answer: (b).Cylinder
With variable thermal conductivity, Fourier law of heat conduction through a plane wall can be expressed as
Answer: (a).Q = -k0 (1 + β t) A d t/d x
The inner and outer surfaces of a furnace wall, 25 cm thick, are at 300 degree Celsius and 30 degree Celsius. Here thermal conductivity is given by the relation
K = (1.45 + 0.5 * 10¯⁵ t²) KJ/m hr deg

Where, t is the temperature in degree centigrade. Calculate the heat loss per square meter of the wall surface area?
Answer: (c).1745.8 kJ/m² hr
A plane wall of thickness δ has its surfaces maintained at temperatures T₁ and T₂. The wall is made of a material whose thermal conductivity varies with temperature according to the relation k = k₀ T². Find the expression to work out the steady state heat conduction through the wall?
Answer: (b).Q = A k₀ (T₁³ – T₂³)/3 δ
The mean thermal conductivity evaluated at the arithmetic mean temperature is represented by
Answer: (d).km = k0 [1 + β (t1 + t2)/2].
Answer: (a).Slope of temperature curve is constant
If β is greater than zero, then choose the correct statement with respect to given relation
k = k0 (1 +β t)
Answer: (c).k is directly proportional to t
The unit of thermal conductivity doesn’t contain which parameter?
Answer: (b).Pascal
The temperatures on the two sides of a plane wall are t1 and t2 and thermal conductivity of the wall material is prescribed by the relation
K = k0 e^(-x/δ)

Where, k0 is constant and δ is the wall thickness. Find the relation for temperature distribution in the wall?
Answer: (d).t 1 – t x / t 1 – t 2 = x/δ
“If β is less than zero, then with respect to the relation k = k0 (1 + β t), conductivity depends on surface area”. True or false
Answer: (b).False
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